Lakers Looking To Be In The LeBron James Market?

Gary A. Vasquez-US PRESSWIRE

Anytime a big name NBAer is on the trading block or up for free agency the Los Angeles Lakers are rumored as a potential destination. Sometimes those rumors come from legit sources. More often than not its just plain laziness as the Lakers are looked upon as the Yankees of pro hoops willing to pay whatever price to land a big name.

Well in the case of LeBron James potentially joining the Lake Show to team with Dwight Howard in 2014 its’ a combination of all of the above and then some.

For the most part there is no real reason to speculate on the prospects of LBJ6 and DH12 teaming up in Los Angeles. Aside from the musings of Brian Windhorst there really isn’t much to speculate on at the moment.

Then there are the facts of the matter as well.

It’s a fact that James is under contract through 2016. He just so happens to have an opt-out clause for 2014. So before you start getting your #6 purple and gold jerseys printed keep in mind the King holds the keys to his own employment status. So too does Dwight Howard.

Before we can envision the Lakers pairing Howard and James we’d first have to see Iron Man under contract for the foreseeable future. Currently Howard is still singing the free agency song looking to maximize his worth on the open market no matter the outcome of this season.

Now what truly makes this LeBron in L.A. scenario so ideal are the rumblings of Kobe Bryant calling it quits in two years time. That would be in 2014 for those that aren’t as dialed in when it comes to math. That would also free up plenty of cash for Mitch Kupchak to toss at James should he seek to make another career decision.

But this is all pie in the sky stuff at the moment. Rest assured that if James creates the dynasty in Miami he envisioned there is no way he’d take his talents to Venice Beach. So for now let’s just focus on what’s in front of us. Kobe needs to equalize Jordan first then retire second. Anything else is for the barbershop at this point.

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