Lakers Rumors: Why the Los Angeles Lakers will not trade for George Hill

By Jason Reed | Nov 19, 2020

MILWAUKEE, WISCONSIN - DECEMBER 19: George Hill #3 of the Milwaukee Bucks is defended by Avery Bradley #11 of the Los Angeles Lakers during a game at Fiserv Forum on December 19, 2019 in Milwaukee, Wisconsin. NOTE TO USER: User expressly acknowledges and agrees that, by downloading and or using this photograph, User is consenting to the terms and conditions of the Getty Images License Agreement. (Photo by Stacy Revere/Getty Images) /

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(Photo by Omar Rawlings/Getty Images) – Los Angeles Lakers /

1. George Hill is a bit redundant after trading for Dennis Schroder

The Los Angeles Lakers do need to figure some things out at the guard position. Both Kentavious Caldwell-Pope and Avery Bradley have opted-out of their player options and the Lakers are going to have to come to terms with at least one of them.

They are likely going to have to add some depth in free agency as well just as a precautionary measure.

However, just because that is a needed action by the Lakers does not mean the team should go out and trade for Hill. Yes, he is a point guard, but he would be really redundant after already trading for Dennis Schroder.

Hill is a secondary ballhandler that would be a great asset to bring off of the bench and essentially be exactly what Rajon Rondo was last season. The problem is that Schroder is already going to be tasked with that role, likely coming off the bench as the Lakers’ sixth man.

The Lakers need guys in the backcourt that they can start alongside LeBron James who do not need the basketball — like an Avery Bradley or KCP. These guys are off-ball threats. While Hill shot tremendously last season, he is most effective as that secondary point guard.

If he was a wing player then it would be a different story but right now. The Lakers need to add another wing (or two) after trading Danny Green and have been connected to Hill’s teammate in Milwaukee, Wesley Matthews.

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